Answer :

Let x and y be number of kilograms of bran and rice.

According to the question,

80x + 100y , 40x + 30y

Minimize Z = 5x + 4y

The feasible region determined 80x + 100y , 40x + 30y is given by

The feasible region is unbounded. The corner points of feasible region are A(0,1.2) , B(0.6,0.4) , C(1.1,0).The value of Z at corner points are

The minimum value of Z is 4.6 at point (0.6,0.4).

Hence, the diet should contain 0.6 kgs of bran and 0.4 kgs of rice for achieving minimum cost of Rs.4.6.

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