Let the manufacturer manufacture x and y numbers of type 1 and type 2trunks.
∴According to the question,
3X + 3y
Maximize Z = 30x + 25y
The feasible region determined 3X + 3y is given by
The corner points of feasible region are A(0,0) , B(0,6) , C(3,3) , D(5,0).The value of Z at corner point is
The maximum value of Z is165 and occurs at point (3,3).
The manufacturer should manufacture 3 trunks of each type to earn maximum profit of Rs.165.
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