Let x and y be number of kilograms of food X and Y.
∴According to the question,
x + 2y , 2x + 2y
Minimize Z = 6x + 10y
The feasible region determined x + 2y , 2x + 2y is given by
The feasible region is unbounded. The corner points of feasible region are A(0,8) , B(1,5) , C(2,4) , D(10,0).The value of Z at corner points are
The minimum value of Z is 52 at point (2,4).
Hence, the diet should contain 2 kgs of food X and 4 kgs of food Y for the least cost of Rs. 52.
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