Answer :


Let x and y be number of A and B trees.


According to the question,


20x + 25y , 10x + 20y


Maximize Z = 40x + 60y


The feasible region determined by 20x + 25y , 10x + 20y is given by



The corner points of feasible region are A(0,0) , B(0,50) , C(20,40), D(70,0).The value of Z at corner points are



The maximum value of Z is 3200 at point (20,40).


Hence, the man should plant 20 A trees and 40 B trees to make maximum profit of Rs.3200.


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