Let x and y be number of A and B trees.
∴According to the question,
20x + 25y , 10x + 20y
Maximize Z = 40x + 60y
The feasible region determined by 20x + 25y , 10x + 20y is given by
The corner points of feasible region are A(0,0) , B(0,50) , C(20,40), D(70,0).The value of Z at corner points are
The maximum value of Z is 3200 at point (20,40).
Hence, the man should plant 20 A trees and 40 B trees to make maximum profit of Rs.3200.
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