Let x and y be number of A and B products.
∴According to the question,
0.5x + y , 200x + 300y
Maximize Z = 20x + 30y
The feasible region determined by 0.5x + y , 200x + 300y is given by
The corner points of feasible region are A(14,33) , B(14,24) , C(26,16), D(48,16).The value of Z at corner points are
The maximum value of Z is 1440 at point (48,16).
Hence, the manufacturer should manufacture 48 A products and 16 B products to maximize their profit of Rs.1440.
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