Let x and y be number of soaps be manufactured of 1st and 2nd type.
∴According to the question,
2x + 3y 480 , 3x + 5y 480, x , y
Maximize Z = 0.25x + 0.50y
The feasible region determined by 2x + 3y 480 , 3x + 5y 480, x , y is given by
The corner points of feasible region are A(0,96) , B(0,0) , C(160,0).
The value of Z at corner points are
The maximum value of Z is 48 at point (0,96).
Hence, the manufacturer should make 96 soaps of the 2nd type to make maximum profit.
Rate this question :