Q. 75.0( 1 Vote )

One of the two ev

Answer :

Let A and B are two events.


As, out of 2 events A and B only one can happen at a time which means no event have anything common.


We can say that A and B are mutually exclusive events.


By definition of mutually exclusive events we know that:


P(A B) = P(A) + P(B)


According to question one event must happen.


This implies A or B is a sure event.


P(A B) = P(A) + P(B) = 1 …Equation 1


Given, P(A) = (2/3)P(B)


To find: odds in favour of B




P(B’) = 1 – 3/5 = 2/5


Odd in favour of B =


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