Q. 75.0( 1 Vote )

# One of the two ev

Answer :

Let A and B are two events.

As, out of 2 events A and B only one can happen at a time which means no event have anything common.

We can say that A and B are mutually exclusive events.

By definition of mutually exclusive events we know that:

P(A B) = P(A) + P(B)

According to question one event must happen.

This implies A or B is a sure event.

P(A B) = P(A) + P(B) = 1 …Equation 1

Given, P(A) = (2/3)P(B)

To find: odds in favour of B  P(B’) = 1 – 3/5 = 2/5

Odd in favour of B = Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

A natural number RD Sharma - Mathematics

In a single throwRD Sharma - Mathematics

One of the two evRD Sharma - Mathematics

A card is drawn aRD Sharma - Mathematics

One of the two evRD Sharma - Mathematics

The probability tRD Sharma - Mathematics

If the probabilitRD Sharma - Mathematics

Without repetitioRD Sharma - Mathematics

6 boys and 6 girlRD Sharma - Mathematics