Q. 275.0( 3 Votes )

If A and B are mu

Answer :

Given A and B are two mutually exclusive events


And, P(A) = 0.35 P(B) = 0.45


By definition of mutually exclusive events we know that:


P(A B) = P(A) + P(B)


We have to find-


i) P(A B) = P(A) + P(B) = 0.35 + 0.45 = 0.8


ii) P(A B) = 0 { nothing is common between A and B}


iii) P(A B’) = This indicates only the part which is common with A and not B This indicates only A.


P(only A) = P(A) – P(A B)


As A and B are mutually exclusive So they don’t have any common parts P(A B) = 0


P(A B’) = P(A) = 0.35


iv) P(A’ B) = P(A B)’ {using De Morgan’s Law}


P(A’ B) = 1 P(A B) = 1 – 0.8 = 0.2


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