Answer :

Given, Sample space is the set of first 200 natural numbers.

∴ n(S) = 200

Let A be the event of choosing the number such that it is divisible by 6

∴ n(A) = [200/6] = [33.334] = 33 {where [.] represents Greatest integer function}

∴ P(A) =

Let B be the event of choosing the number such that it is divisible by 8

∴ n(B) = [200/8] = [25] = 25 {where [.] represents Greatest integer function}

∴ P(B) =

We need to find the P(such that number chosen is divisible by 6 or 8)

∵ P(A or B) = P(A ∪ B)

Note: By definition of P(E or F) under axiomatic approach(also called addition theorem) we know that:

P(E ∪ F) = P(E) + P(F) – P(E ∩ F)

∴ P(A ∪ B) = P(A) + P(B) – P(A ∩ B)

We don’t have value of P(A ∩ B) which represents event of choosing a number such that it is divisible by both 4 and 6 or we can say that it is divisible by 24.

n(A ∩ B) = [200/24] = [8.33] = 8

∴ P(A ∩ B) =

∴ P(A ∪ B) =

Rate this question :

A natural number RD Sharma - Mathematics

In a single throwRD Sharma - Mathematics

One of the two evRD Sharma - Mathematics

A card is drawn aRD Sharma - Mathematics

One of the two evRD Sharma - Mathematics

The probability tRD Sharma - Mathematics

If the probabilitRD Sharma - Mathematics

Without repetitioRD Sharma - Mathematics

6 boys and 6 girlRD Sharma - Mathematics