Q. 175.0( 1 Vote )

# A bag contains 6

given: bag which contains 6 red, 8 blue and 4 white balls

formula:

two balls are drawn at random, therefore

total possible outcomes are 18C3

therefore n(S)=816

(i) let E be the event of getting one red and two white balls

E= {(W) (W) (R)}

n(E)= 6C14C2=36

(ii) let E be the event of getting two blue and one red

E= {(B) (B) (R)}

n(E)= 8C26C1=168

(iii) let E be the event that one of the balls must be red

E= {(R) (B) (B)} or {(R) (W) (W)} or {(R) (B) (W)}

n(E)= 6C14C18C1+6C14C2+6C18C2=396

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