Answer :

Given that, a die is thrown 5 times.


Let p be the probability of getting an odd number in a throw.


Since there are 6 possible outcomes in a throw of a die. That is, {1, 2, 3, 4, 5, 6}


And there are 3 odd numbers out of these 6 outcomes. That is, {1, 3, 5}




Then, let q be the probability of getting an even number in a throw.


And we know that, p + q = 1


q = 1 – p




Let X be a random variable representing a number of odd numbers in n throw of a die.


Then, the probability of getting r odd numbers out of n throw of the die can be given as,


P (X = r) = nCrprqn-r


Here, n = 5


Putting values of n, p, and q in the above formula. We get




…(i)


We need to find the probability that an odd number will come up exactly three times.


It is given by,


Probability = P (X = 3)


Put r = 3 in equation (i) to find P (X = 3), we get








Thus, the probability of getting an odd number to come up exactly three times is 5/16.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

A box has 100 penMathematics - Exemplar

State True or FalMathematics - Exemplar

A random variableMathematics - Board Papers

How many times muMathematics - Board Papers

A card from a pacMathematics - Board Papers

An experiment sucMathematics - Board Papers

A bag A contains Mathematics - Board Papers

On a multiple choMathematics - Board Papers

Mark the correct RD Sharma - Volume 2