Q. 74.0( 2 Votes )

For a group of 20

Answer :

To Find: Find the correct mean and standard deviation.


Explanation: Here, n=200,


X =




Since, the score was incorrect,


Now, The sum is incorrect


Corrected


8000-7


The correct score is 7993


So, The mean of correct score =



Mean = 39.95


Now, Standard variance = 15


Since, Variance =


Variance = 255


X =


255 =


255 =




Now, the correct
-342-532+432+352


365000-1156-2809+1849+1225



Corrected Variance =



1820.54-1596.40


Corrected variance =224.14


Now, Corrected Standard Deviation =



Correct Deviation is 14.97


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

The sum and the sRS Aggarwal - Mathematics

If x1,RD Sharma - Mathematics

The mean and variRS Aggarwal - Mathematics

If the sum of theRD Sharma - Mathematics

The mean and stanRS Aggarwal - Mathematics

Following are theRD Sharma - Mathematics

The mean and variRS Aggarwal - Mathematics

The following resRS Aggarwal - Mathematics

Coefficient of vaRS Aggarwal - Mathematics

The following resRS Aggarwal - Mathematics