Q. 19

# In a hurdles race, a player has to cross 10 hurdles. The probability that he will clear each hurdle is (5/6). What is the probability that he will knock down fewer than 2 hurdles?

Answer :

The probability that the hurdle will be cleared is 5/6

Using Bernoulli’s Trial we have,

P(Success=x) = ^{n}C_{x}.p^{x}.q^{(n-x)}

x=0, 1, 2, ………n and q = (1-p), n =10

p = 5/6 q = 1/6

Probability that he will knock down fewer than 2 hurdles is =

P(0) + P(1)

⇒ ^{10}C_{0}()^{0}()^{10} + ^{10}C_{1}()^{1}()^{9}

⇒

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