Q. 165.0( 1 Vote )

# In roulette, Fig.

Answer :

As player sets Rs 10 on a number ,if he wins he get Rs 100

∴ his profit is Rs 90.

If he loses, he suffers a loss of Rs 10

He gets a profit when ball comes to rest in his selected slot.

Total possible outcome = 13

Favourable outcomes = 1

∴ probability of getting profit = 1/13

And probability of loss = 12/13

If X is the random variable denoting gain and loss of player

∴ X can take values 90 and -10

P(X=90) = 1/13

And P(X=-10) = 12/13

Now we have p_{i} and x_{i.}

Let’s proceed to find mean

Mean of any probability distribution is given by Mean = ∑x_{i}p_{i}

∴ first we need to find the products i.e. p_{i}x_{i} and add them to get mean

Following table representing probability distribution gives the required products :

E(X) = Mean =

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