Answer :

(i) Using Bernoulli’s Trial P(Success=x) = nCx.px.q(n-x)


x=0, 1, 2, ………n and q = (1-p), n =7


the favourable outcomes ,


(1,6), (6,1), (2,5), (5,2), (3,4), (4,3)


The probability of success = p =


q =


probability of no success = 7C0.()0()7


()7


(ii) Using Bernoulli’s Trial P(Success=x) = nCx.px.q(n-x)


x=0, 1, 2, ………n and q = (1-p), n =7


the favourable outcomes ,


(1,6), (6,1), (2,5), (5,2), (3,4), (4,3)


The probability of success = p =


q =


probability of exactly 6 successes = 7C6.()6()1


35.()7


(iii) Using Bernoulli’s Trial P(Success=x) = nCx.px.q(n-x)


x=0, 1, 2, ………n and q = (1-p), n =7


the favourable outcomes ,


(1,6), (6,1), (2,5), (5,2), (3,4), (4,3)


The probability of success = p =


q =


probability of at least 6 successes =


7C6.()6()1 + 7C7.()7()0


36.()7


()5


(iv) Using Bernoulli’s Trial P(Success=x) = nCx.px.q(n-x)


x=0, 1, 2, ………n and q = (1-p), n =7


the favourable outcomes ,


(1,6), (6,1), (2,5), (5,2), (3,4), (4,3)


The probability of success = p =


q =


probability of at least 6 successes =


7C0.()0()7 + 7C1.()1()6 + 7C2.()2()5 + 7C3.()3()4 + 7C4.()4()3 + 7C5.()5()2 + 7C6.()6()1


(1- 7)


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