Let X denote the

Given,

Our variable is X and from equation we see that it is taking values X = 0,1,2,3,4 …… (any whole number)

And it represents the number of colleges in which you are going to get admission.

According to equation given we have :

∴ P(X = 0) = k×0 = 0

P(X = 1) = k×1 = k

P(X = 2) = 2k×2 = 4k

P(X = 3) = k(5-3) = 2k

P(X = 4) = k(5-4) = k

P(X>4) = 0

As in question, it is not given either X is random variable or the given distribution is a probability distribution, we can’t apply any thing directly.

But we have a hint in the question,

As P(X = 0) = 0

It means the chance of not getting admission in any college 0

∴ admission is sure

Hence the sum of all probabilities must be equal to 1 as getting admission has become a sure event.

This makes the given distribution a probability distribution an X a random variable also.

∴ k + 4k+2k+k = 1

8k = 1

k = 1/8

i) P(getting admission in exactly one college) = P(1) = k = 1/8

ii) P(getting admission in atmost 2 colleges) = P(X≤2)

= P(X = 1)+P(X = 2)

= k+4k = 5k = 5/8

iii) P(getting admission in atleast 2 colleges) = P(X≥2)

= P(X = 2)+P(X = 3)+P(X = 4)

= 4k+2k+k = 7k = 7/8