Q. 115.0( 1 Vote )

# Five defective ma

Answer :

X represents the number of defective mangoes drawn.

∴ X can take values 0,1,2 or 3

∵ there are total 20mangoes (15good+5defective) mangoes

n(S) = total possible ways of selecting 5 mangoes =

P(X = 0) = P(selecting no defective mango) =

P(X = 1) = P(selecting 1 defective mango and 3 good mangoes)

=

P(X = 2) = P(selecting 2 defective mangoes and 2 good mangoes)

=

P(X = 3) = P(selecting 3 defective mangoes and 1 good mango)

=

P(X = 4) = P(selecting 4 defective mangoes and no good mango)

=

Now we have p_{i} and x_{i.}

Following table represents the probability distribution of X :

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