Q. 83.8( 5 Votes )

A, B, C are three mutually exclusive and exhaustive events associated with a random experiment.

If P(B) = (3/2) P(A) and P(C) = (1/2) P(B), find P(A).

Answer :

Given : A,B,C are mutually exclusive events and exhaustive events


P(B) = (3/2) P(A) and P(C) = (1/2) P(B)


To find : P(A)


Formula used : P(A) + P(B) + P(C) = 1


For mutually exclusive events A,B,and C , P(A and B) = P(B and C) = P(A and C)= 0


Let P(A) = x , P(B) = (3/2) P(A) = x , P(C) = (1/2) P(B) = x = x


x + x + x = 1


x = 1


x =


P(A) = x =


P(A) =


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