Q. 15

# Two dice are toss

Given : two dice are tossed once

To find : Probability of getting an even number on the first die or a total 8.

The formula used : Probability =

P(A or B) = P(A) + P(B) - P(A and B)

A die is numbered from 1 to 6

When two dice are tossed once, total number of outcomes = 62 = 36

Let A denote the event of getting an even number on the first die and B denote the event of getting a total of 8

For getting an even number on the first die

Favourable outcomes =

{(2,1) ,(2,2) ,(2,3) ,(2,4) ,(2,5) ,(2,6) ,(4,1) ,(4,2) ,(4,3) ,(4,4) ,(4,5) ,(4,6) , (6,1) ,(6,2) ,(6,3) ,(6,4) ,(6,5) ,(6,6) }

Favourable number of outcomes = 18

Probability of getting an even number on the first die = P(A) =

For getting a total of 8

Favourable outcomes =

{ (2,6) , (4,4) , (6,2) ,(5,3) , (3,5) }

Favourable number of outcomes = 5

Probability of getting a total of 8 = P(A) =

For getting an even number on the first die and a total of 8

Favourable outcomes = {(2,6) , (4,4) , (6,2)}

Probability of getting an even number on the first die and a total of 8 = P(A and B) =

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) =

P(A or B) =

Probability of getting an even number on the first die or a total 8 =

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