# Suppose a girl th

Given:

Let us assume D1, D2 and A be the events as follows:

D1 = Throwing die and getting 1 or 2

D2 = Throwing die and getting 3,4,5 or 6

A = getting exactly one tail

P(A|D1) = P(getting 1 tail on getting 1 or 2 from die)

P(A|D2) = P(Getting 1 tail on getting 3,4,5 or 6 from die)

Now we find

P(D2|A) = P(The tail we get here come after getting 3,4,5 or 6 from die)

Using Baye’s theorem:

The required probability is .

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

A bag A contains RD Sharma - Volume 2

The contents of tRD Sharma - Volume 2

A girl throws a dMathematics - Board Papers

Three urns contaiRD Sharma - Volume 2

Two groups are coMathematics - Board Papers

The contents of tRD Sharma - Volume 2

Suppose a girl thMathematics - Board Papers

There are three cMathematics - Board Papers

Given three identMathematics - Board Papers