Q. 43.7( 3 Votes )

The contents of t

Answer :


Urn I has 7 white and 3 black balls

Urn II has 4 white and 6 black balls

Urn III has 2 white and 8 black balls

Let us assume U1, U2, U3 and A be the events as follows:

U1 = choosing Urn I

U2 = choosing Urn II

U3 = choosing Urn III

A = choosing 1 white and 1 red ball from urn

From the problem,

The Probability of choosing balls from each Urn differs from Urn to Urn and the probabilities are as follows:

P(A|U1) = P(Choosing required balls from Urn 1)

P(A|U2) = P(Choosing required balls from Urn 2)

P(A|U3) = P(Choosing required balls from Urn 3)

Now we find

P(U3|A) = P(The chosen balls are from Urn3)

Using Baye’s theorem:

The required probabilities is .

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