Q. 33.5( 2 Votes )

Three urns contai

Answer :


Urn I has 2 white and 3 black balls

Urn II has 3 white and 2 black balls

Urn III has 4 white, 1 black red balls

Let us assume U1, U2, U3 and A be the events as follows:

U1 = choosing Urn I

U2 = choosing Urn II

U3 = choosing Urn III

A = choosing 1 white ball from an urn

We know that each urn is most likely to choose. So, probability of choosing a urn will be same for every Urn.

The Probability of choosing balls from each Urn differs from Urn to Urn and the probabilities are as follows:

P(A|U1) = P(Choosing white ball from Urn 1)

P(A|U2) = P(Choosing white ball from Urn 2)

P(A|U3) = P(Choosing required balls from Urn 3)

Now we find

P(U1|A) = P(The chosen balls are from Urn1)

Using Baye’s theorem:

The required probabilities is .

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

A bag A contains RD Sharma - Volume 2

The contents of tRD Sharma - Volume 2

A girl throws a dMathematics - Board Papers

Three urns contaiRD Sharma - Volume 2

Two groups are coMathematics - Board Papers

The contents of tRD Sharma - Volume 2

Suppose a girl thMathematics - Board Papers

There are three cMathematics - Board Papers

Given three identMathematics - Board Papers