# Three urns contai

Given:

Urn I has 2 white and 3 black balls

Urn II has 3 white and 2 black balls

Urn III has 4 white, 1 black red balls

Let us assume U1, U2, U3 and A be the events as follows:

U1 = choosing Urn I

U2 = choosing Urn II

U3 = choosing Urn III

A = choosing 1 white ball from an urn

We know that each urn is most likely to choose. So, probability of choosing a urn will be same for every Urn.

The Probability of choosing balls from each Urn differs from Urn to Urn and the probabilities are as follows:

P(A|U1) = P(Choosing white ball from Urn 1)

P(A|U2) = P(Choosing white ball from Urn 2)

P(A|U3) = P(Choosing required balls from Urn 3)

Now we find

P(U1|A) = P(The chosen balls are from Urn1)

Using Baye’s theorem:

The required probabilities is .

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