Q. 275.0( 1 Vote )

# There are t

Given:

Coin 1 is two heads, coin2 is biased and coin 3 is unbiased

Let us assume U1, U2, U3 and A be the events as follows:

U1 = choosing coin 1

U2 = choosing coin 2

U3 = choosing coin 3

We know that each coin is most likely to choose. So, probability of choosing a coin will be same for every coin.

From the problem

P(A|U1) = P(getting heads on tossing coin 1)

P(A|U2) = P(getting heads on tossing coin 2)

P(A|U3) = P(getting heads on tossing coin 3)

Now we find

P(U1|A) = P(The coin tossed to get head is Coin 1)

Using Baye’s theorem:

The required probability is .

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