Q. 275.0( 1 Vote )

There are t

Answer :


Coin 1 is two heads, coin2 is biased and coin 3 is unbiased

Let us assume U1, U2, U3 and A be the events as follows:

U1 = choosing coin 1

U2 = choosing coin 2

U3 = choosing coin 3

A = getting heads

We know that each coin is most likely to choose. So, probability of choosing a coin will be same for every coin.

From the problem

P(A|U1) = P(getting heads on tossing coin 1)

P(A|U2) = P(getting heads on tossing coin 2)

P(A|U3) = P(getting heads on tossing coin 3)

Now we find

P(U1|A) = P(The coin tossed to get head is Coin 1)

Using Baye’s theorem:

The required probability is .

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

A bag A contains RD Sharma - Volume 2

The contents of tRD Sharma - Volume 2

A girl throws a dMathematics - Board Papers

Three urns contaiRD Sharma - Volume 2

Two groups are coMathematics - Board Papers

The contents of tRD Sharma - Volume 2

Suppose a girl thMathematics - Board Papers

There are three cMathematics - Board Papers

Given three identMathematics - Board Papers