Q. 215.0( 3 Votes )

A bag conta

Answer :


Bag I has 1 white and 6 red balls

Bag II has 4 white and 3 red balls

Let us assume U1, U2 and A be the events as follows:

U1 = choosing Bag I

U2 = choosing Bag II

A = choosing white ball from urn

We know that each bag is most likely to choose. So, probability of choosing a bag will be same for every bag.

The Probability of choosing ball from each Bag differs from Bag to Bag and the probabilities are as follows:

P(A|U1) = P(Choosing white ball from Bag I)

P(A|U2) = P(Choosing white ball from Bag II)

Now we find

P(U1|A) = P(The chosen ball is from Bag I)

Using Baye’s theorem:

The required probabilities are .

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

A bag A contains RD Sharma - Volume 2

The contents of tRD Sharma - Volume 2

A girl throws a dMathematics - Board Papers

Three urns contaiRD Sharma - Volume 2

Two groups are coMathematics - Board Papers

The contents of tRD Sharma - Volume 2

Suppose a girl thMathematics - Board Papers

There are three cMathematics - Board Papers

Given three identMathematics - Board Papers