Answer :

Given:


Coin 1 has heads on both sides


Coin 2 and 3 are biased coins


Let us assume U1, U2, U3 and A be the events as follows:


U1 = choosing coin 1


U2 = choosing coin 2


U3 = choosing coin 3


A = getting head on tossing the coin


We know that each coin is most likely to choose. So, probability of choosing a coin will be same for every coin.





From the problem:


P(A|U1) = P(getting head on tossing coin 1)



P(A|U2) = P(getting head on tossing coin 2)



P(A|U3) = P(getting head on tossing coin 3)



Now we find


P(U1|A) = P(The head we get after is from tossing coin 1)


Using Baye’s theorem:







The required probability is .


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