# The contents of <

Given:

Bag I contains 1 white, 2 black and 3 red balls

Bag II contains 2 white, 1 black and 1 red ball

Bag III contains 4 white, 5 black and 3 red balls

A bag is chosen and two balls are drawn from it.

There are three mutually exclusive ways to draw a white and a red ball from one of the three bags –

a. Bag I is selected, and then, a white and a red ball are drawn from bag I

b. Bag II is selected, and then, a white and a red ball are drawn from bag II

c. Bag III is selected, and then, a white and a red ball are drawn from bag III

Let E1 be the event that bag I is selected, E2 be the event that bag II is selected and E3 be the event that bag III is selected.

Since there are only three bags and each bag has an equal probability of being selected, we have

Let E4 denote the event that a white and a red ball are drawn.

Hence, we have

We also have

Similarly, we also have

Using the theorem of total probability, we get

P(E4) = P(E1)P(E4|E1) + P(E2)P(E4|E2) + P(E3)P(E4|E3)

Thus, the probability of the drawn balls being white and red is.

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