# Arun and Tarun appeared for an interview for two vacancies. The probability of Arun’s selections is 1/4 and that of Tarun’s rejection is 2/3. Find the probability that at least one of them will be selected.

Given that,

P(AS) = P(Arun’s selection)

P(AN) = P(Arun’s rejection)

P(TN) = P(Tarun’s rejection)

P(TS) = P(Tarun’s selection)

We need to find the probability that at least one of them will be selected

P(Satone) = P(Selecting at least one of them)

P(Satone) = P(selecting only Arun) + P(selecting only Tarun) + P(Selecting both)

Since selection of each person is an independent event their probabilities multiply each other

The required probability is .

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses