Q. 95.0( 2 Votes )

Arun and Ta

Answer :

Given that,


P(AS) = P(Arun’s selection)



P(AN) = P(Arun’s rejection)




P(TN) = P(Tarun’s rejection)



P(TS) = P(Tarun’s selection)




We need to find the probability that at least one of them will be selected


P(Satone) = P(Selecting at least one of them)


P(Satone) = P(selecting only Arun) + P(selecting only Tarun) + P(Selecting both)


Since selection of each person is an independent event their probabilities multiply each other






The required probability is .


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

A bag contains 6 RD Sharma - Volume 2

A man is known toMathematics - Board Papers

A bag contaRD Sharma - Volume 2

Three persons A, Mathematics - Board Papers

Bag I contains 3 Mathematics - Board Papers

A speaks trRD Sharma - Volume 2

Two cards aRD Sharma - Volume 2

A bag contaRD Sharma - Volume 2

Kamal and MRD Sharma - Volume 2

Two balls aRD Sharma - Volume 2