Q. 85.0( 3 Votes )

A bag contains 8 red and 6 green balls. Three balls are drawn one after another without replacement. Find the probability that at least two balls drawn are green.

Answer :

Given:


Bag contains 8 red and 6 green balls


It is told that three balls are drawn without replacement.


We need to find the probability that at least two balls drawn are green.


The possible cases of drawing balls are as shown below:


i. Green,Green,Red


ii. Green,Red,Green


iii. Red,Green,Green


iv. Green,Green,Green


P(Dat2greens) = P(GGR) + P(GRG) + P(RGG) + P(GGG)


Since drawing balls are independent events so, the probabilities multiply each other.







The required probability is .


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