Answer :

Given that,


P(KS) = P(Kamal’s selection)



P(KN) = P(Not selecting Kamal)




P(VS) = P(Monika’s selection)



P(VN) = P(Not selecting Monika)




We need to find:


i. Both of them will be selected


ii. None of them will be selected


iii. At least one of them will be selected


iv. Only one of them will be selected.


P(Sboth) = P(Both of them are selected)


Since selection of each person is an independent event their probabilities multiply each other





P(Snone) = P(None of them are selected)


Since selection of each person is an independent event their probabilities multiply each other





P(Satone) = P(Selecting at least one of them)


P(Satone) = P(selecting only Kamal) + P(selecting only Monika) + P(Selecting both)


Since selection of each person is an independent event their probabilities multiply each other






P(Sone) = P(Only one of them is selected)


P(Sone) = P(only Kamal is selected) + P(only Monika is selected)


Since selection of each person is an independent event their probabilities multiply each other





The required probabilities are .


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

A bag contains 6 RD Sharma - Volume 2

A man is known toMathematics - Board Papers

A bag contaRD Sharma - Volume 2

Three persons A, Mathematics - Board Papers

Bag I contains 3 Mathematics - Board Papers

A speaks trRD Sharma - Volume 2

Two cards aRD Sharma - Volume 2

A bag contaRD Sharma - Volume 2

Kamal and MRD Sharma - Volume 2

Two balls aRD Sharma - Volume 2