# An urn contains 7 red and 4 blue balls. Two balls are drawn at random with replacement. Find the probability of getting.i. 2 red ballsii. 2 blue ballsiii. One red and one blue ball

Given:

Urn contains 7 red and 4 blue balls

It is told that two balls are drawn with replacement

Let us find the probability of drawing each marble from bag

P(B) = P(Drawing a Blue Ball)

P(R) = P(Drawing a Red Ball)

We need to find the probability that the balls drawn:

i. Both in red colour

ii. Both in blue colour

iii. One red and one blue

P(SRR) = P(drawing Two red colour balls)

Since drawing a ball is an independent event, the probabilities multiply each other.

P(SBB) = P(drawing two blue colour balls)

Since drawing a ball is independent for each bag, the probabilities multiply each other.

P(Sany) = P(drawing Blue and red ball in any order)

P(Sany) = P(drawing Blue ball followed by red) + P(drawing Red ball followed by Blue)

Since drawing a ball is an independent event, the probabilities multiply each other.

.

The required probabilities are .

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