# Two balls a

Given:

Bag contains 10 black balls and 8 red balls

It is told that two balls are drawn from bag with replacement.

Let us find the Probability of drawing each colour ball from the bag.

P(B1) = P(drawing black ball from bag)   P(R1) = P(drawing red ball from bag)   We need to find:

(i) P(Drr) = P(both balls drawn are red)

(ii) P(Dbr) = P(first drawn is black and next is red)

(iii) P(Srd) = P(one ball is red and other is black)

P(Drr) = P(both balls drawn are red)

Since drawing a ball is independent for each bag, the probabilities multiply each other.   P(Dbr) = P(first drawn is black and next is red)

Since drawing a ball is independent for each bag, the probabilities multiply each other.   P(Srb) = P(one ball is red and other is black)

P(Srb) = P(first drawn is red and next is black) + P(first drawn black and next is red)

P(Srb) = P(Drb) + P(Dbr)

Since drawing a ball is independent for each bag, the probabilities multiply each other.    The required probabilities are .

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