Q. 215.0( 2 Votes )

A can hit a

Answer :


A hits a target 3 times out of 6 shots

B hits a target 2 times out of 6 shots

C hits a target 4 times out of 4 shots

P(TA) = P(A hits target)

P(TB) = P(B hits target)

P(TC) = P(C hits target)

P(NA) = P(A doesn’t hits target)

P(NB) = P(B doesn’t hits target)

P(NC) = P(C doesn’t hits target)


It is told that the target is to be hit by at least two shots. This is only possible when at least two of the Persons hits the target.


Since hitting by a person is independent the probabilities will multiply each other.

P(M) = (P(TA)P(TB)P(NC)) + (P(TA)P(NB)P(TC)) + (P(NA)P(TB)P(Tc)) + (P(TA)P(TB)P(TC))


The required probability is .

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

A bag contains 6 RD Sharma - Volume 2

A man is known toMathematics - Board Papers

A bag contaRD Sharma - Volume 2

Three persons A, Mathematics - Board Papers

Bag I contains 3 Mathematics - Board Papers

A speaks trRD Sharma - Volume 2

Two cards aRD Sharma - Volume 2

A bag contaRD Sharma - Volume 2

Kamal and MRD Sharma - Volume 2

Two balls aRD Sharma - Volume 2