Answer :

Given that,

⇒ P(H_{S}) = P(Husband’s selection)

⇒

⇒ P(H_{N}) = P(Not selecting Husband)

⇒

⇒

⇒ P(W_{S}) = P(wife’s selection)

⇒

⇒ P(W_{N}) = P(Not selecting Wife)

⇒

⇒

We need to find:

i. Both of them will be selected

ii. Only one of them will be selected

iii. None of them will be selected

⇒ P(S_{both}) = P(Both of them are selected)

Since selection of each person is an independent event their probabilities multiply each other

⇒

⇒

⇒

⇒ P(S_{one}) = P(Only one of them is selected)

⇒ P(S_{one}) = P(only Husband is selected) + P(only Wife is selected)

Since selection of each person is an independent event their probabilities multiply each other

⇒

⇒

⇒

⇒ P(S_{none}) = P(None of them are selected)

Since selection of each person is an independent event their probabilities multiply each other

⇒

⇒

⇒

∴ The required probabilities are .

Rate this question :

A bag contains 6 RD Sharma - Volume 2

A man is known toMathematics - Board Papers

A bag contaRD Sharma - Volume 2

Three persons A, Mathematics - Board Papers

Bag I contains 3 Mathematics - Board Papers

A speaks trRD Sharma - Volume 2

Two cards aRD Sharma - Volume 2

A bag contaRD Sharma - Volume 2

Kamal and MRD Sharma - Volume 2

Two balls aRD Sharma - Volume 2