# Tickets are

Given that tickets are numbered from 1 to 10.

It is told that two tickets are drawn one after other in random.

We need to find the probability that number on ticket is a multiple of 5 and other number is multiple of 4.

Let us find the individual probabilities first

P(T51) = P(Number on ticket is multiple of 5 in 1st draw)   P(T41) = P(Number on ticket is multiple of 4 in 1st draw)   P(T52) = P(Number on ticket is multiple of 5 in 2nd draw)  P(T42) = P(Number on ticket is multiple of 4 in 2nd draw)  P(D54) = P(Drawing one ticket which is multiple of 5 and other is multiple of 4)

P(D54) = P(Drawing 5 multiple ticket first and 4 multiple ticket next) + (P(Drawing 4 multiple ticket first and 5 multiple ticket next)

Since drawing tickets are independent their probabilities multiply each other,

P(D54) = (P(T51)P(T42)) + (P(T41)P(T52))   The required probability is .

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

A bag contains 6 RD Sharma - Volume 2

A man is known toMathematics - Board Papers

A bag contaRD Sharma - Volume 2

Three persons A, Mathematics - Board Papers

Bag I contains 3 Mathematics - Board Papers

A speaks trRD Sharma - Volume 2

Two cards aRD Sharma - Volume 2

A bag contaRD Sharma - Volume 2

Kamal and MRD Sharma - Volume 2

Two balls aRD Sharma - Volume 2