Q. 145.0( 2 Votes )

A bag contains 3 red and 2 black balls. One ball Is drawn from it at random. Its colour is noted and then it is put back in the bag. A second draw is made and the same procedure is repeated. Find the probability of drawing (i) tow red balls, (ii) two black balls, (iii) first red and second black ball.

Answer :

Given, bag contains 3 red and 2 black balls.


Probability of getting red ball=


Probability of getting black ball=


(i) two red balls


P(getting two getting red balls)=P(A)*P(A)



(ii) two black balls


P(getting two black balls)=P(B)*P(B)



(iii) first red and second black ball.


P( getting first red and second black ball)=P(A)*P(B)



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