Q. 8 C5.0( 2 Votes )

# A coin is tossed three times. Find P (A/B) in each of the following:A=At most two tails, B=At least one tail.

When a coin is tossed three times, we have following outcomes

{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}

Total outcomes =8

A= atmost two tails ={HHH, HHT, HTH, THH, HTT, THT, TTH, } = 7

Therefore probability of occurrence of event A = P(A) = B= at least one tail ={HHT, HTH, HHT, THT, TTH, TTT, HTT} =7

Therefore probability of occurrence of event B = P(B) = Now Also we want P (A B) = probability of occurrence of both events A and B

= occurrence of atleast two tail and atleast one tail ={HHT, HTH, THH, HTT, THT, TTH,} =6

Hence, probability of occurrence of both events A and B = P (A B)= Therefore, = = (answer)

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