Q. 8 B5.0( 3 Votes )

A coin is tossed three times. Find P (A/B) in each of the following:

A=At least two heads, B=At most two heads

Answer :

When a coin is tossed three times, we have following outcomes


{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}


Total outcomes =8


A= at least two heads ={HHH, HHT, THH, HTH} = 4


Therefore probability of occurrence of event A = P(A) =


B= at most two heads ={HHT, HTH, HHT, THT, TTH, TTT, HTT} =7


Therefore probability of occurrence of event B = P(B) =


Now Also we want P (A B) = probability of occurrence of both events A and B


= occurrence of atleast and atmost two heads ={HHT, HTH, THH} =3


Hence, probability of occurrence of both events A and B = P (A B)=


Therefore, =


= (answer)


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