Q. 175.0( 3 Votes )

A pair of dice is thrown. Find the probability of getting the sum 8 or more, if 4 appears on the first die.

Answer :

We know, when a pair of dice is thrown, total possible outcomes are = 36


A=No of outcomes for getting sum of 8 or more are


{(2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5),(6,6)} = 15


Therefore, P(A) =


B= No of outcomes for first die showing 4 =


{(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)} = 6


Hence P(B) =


(A B) = outcomes of getting sum as 8 or more with a first die showing 4


= {(4,4),(4,5),(4,6)} = 3


Hence P(A B) =


Therefore, = (answer)


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