Q. 145.0( 3 Votes )

A pair of dice is thrown. Find the probability of getting 7 as the sum, if it is known that the second die always exhibits an odd number.

Answer :

We know total possible outcomes when two dice are thrown = 36


A= sum is 7


{(1,6),(2,5),(3,4),(4,3),(5,2),(6,1l} = 6


P(A) =


B =second die exhibit odd number


{(1,1),(1,3),(1,5),(2,1),(2,3),(2,5),(3,1),(3,3),(3,5),(4,1),(4,3),(4,5),(5,1),(5,3),(5,5),(6,1),(6,3),(6,5)}= 18


P(B) =


(A B) = sum of two number is 7 and also second die exhibit odd number


={(2,5),(4,3),(6,1)} =3


P(A B) =


Therefore, =


= (answer)


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :