Q. 135.0( 1 Vote )

Two dice are thrown. Find the probability that the numbers appeared has the sum 8, if it is known that the second die always exhibits 4.

Answer :

We know total possible outcomes when two dice are thrown = 36

A= sum is 8

{(2,6),(3,5),(4,4),(5,3),(6,2)} = 5

P(A) =

B =second die exhibit 4

{(1,4),(2,4),(3,4),(4,4),(5,4),(6,4)}= 6

P(B) =

(A B) = sum of two number is 8 and also second die exhibit 4

=(4, 4) =1

P(A B) =

Therefore, = (answer)

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