Q. 135.0( 1 Vote )

Two dice are thrown. Find the probability that the numbers appeared has the sum 8, if it is known that the second die always exhibits 4.

Answer :

We know total possible outcomes when two dice are thrown = 36


A= sum is 8


{(2,6),(3,5),(4,4),(5,3),(6,2)} = 5


P(A) =


B =second die exhibit 4


{(1,4),(2,4),(3,4),(4,4),(5,4),(6,4)}= 6


P(B) =


(A B) = sum of two number is 8 and also second die exhibit 4


=(4, 4) =1


P(A B) =


Therefore, = (answer)


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