Q. 115.0( 1 Vote )

Mother, father and son line up at random for a family picture. If A and B are two events given by A=son on one end, B= Father in the middle, find P (A/B) and P (B/A).

Answer :

Total possible outcomes =


{FMS, FSM, MFS, SMF, SFM, MSF} =6


A= Son on end = {FMS, MFS, SMF, SFM} =4


Therefore P(A) =


B= father in middle = {MFS, SFM} = 2


Therefore P(B) =


(A B) = son on one end and father in middle


= {MFS, SFM} =2


P(A B) =


Hence = (answer)


. = (answer)


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