Q. 75.0( 4 Votes )

A bag contains 20

Answer :

There are 20 tickets numbered from 1 to 25, so the sample space is


S = {1, 2, 3, …., 20}, n(S) = 20


Number of even numbered tickets from 1 to 20 is


{2, 4, 6, 8, 10, 12, 14, 16, 18, 20} = 10


Number of odd numbered tickets from 1 to 20 is


{1, 3, 5, 7, 9, 11, 13, 15, 17, 19} = 10


Let A represents first ticket with even number and B represents second ticket with odd number


Then the probability of first ticket having even number and second ticket having odd number without replacement is



(as there are 10 even numbered tickets out of 20 tickets in first draw, and 10 odd numbered tickets out of 19 tickets in second draw as the tickets are not replaced)


Hence the required probability is


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

A bag contains 6 RD Sharma - Volume 2

A man is known toMathematics - Board Papers

A bag contaRD Sharma - Volume 2

Three persons A, Mathematics - Board Papers

Bag I contains 3 Mathematics - Board Papers

A speaks trRD Sharma - Volume 2

Two cards aRD Sharma - Volume 2

A bag contaRD Sharma - Volume 2

Kamal and MRD Sharma - Volume 2

Two balls aRD Sharma - Volume 2