# A bag contains 25 tickets, numbered from 1 to 25. A ticket is drawn and then another ticket is drawn without replacement. Find the probability that both tickets will show even numbers.

There are 25 tickets numbered from 1 to 25, so the sample space is

S = {1, 2, 3, …., 25}, n(S) = 25

Number of even numbered tickets from 1 to 25 is

{2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24} = 12

Let A represents first ticket with even number and B represents second ticket with even number

Then the probability of both tickets being even number without replacement is

P(both tickets showing even number without replacement)

(as there are 12 even numbered tickets out of 25 tickets in first draw, and 11 even numbered tickets out of 24 tickets in second draw as the tickets are not replaced)

Hence the required probability is

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses