Q. 124.0( 2 Votes )

# <span lang="EN-US

Answer :

Given : 20% of the bulbs produced by a machine are defective.

To find probability distribution of a number of defective bulbs in a sample of 4 bulbs chosen at random.

Formula used :

The probability distribution table is given by ,

Where P(x) = ^{n}C_{x}

Here p is the probability of getting a defective bulb.

q = 1 – p

Let the total number of bulbs produced by a machine be x

20% of the bulbs produced by a machine are defective.

Number of defective bulbs produced by a machine = =

X denotes the number of defective bulbs in a sample of 4 bulbs chosen at random.

Let p be the probability of getting a defective bulb,

p = =

p =

q = 1 – p = 1 - =

q =

since 4 bulbs are chosen at random, n = 4

X can take the values of 0,1,2,3,4

P(x) = ^{n}C_{x}

P(0) = ^{4}C_{0} =

P(1) = ^{4}C_{1} =

P(2) = ^{4}C_{2} =

P(3) = ^{4}C_{3} =

P(4) = ^{4}C_{4} =

The probability distribution table is as follows,

Rate this question :

An urn contains 3Mathematics - Board Papers

Two cards are draMathematics - Board Papers

There are three cMathematics - Board Papers

Three numbers areMathematics - Board Papers

Let <span lang="EMathematics - Board Papers

Which of the follRD Sharma - Volume 2

Which of the follRD Sharma - Volume 2

A random variableRD Sharma - Volume 2