# <span lang="EN-US

Given : 20% of the bulbs produced by a machine are defective.

To find probability distribution of a number of defective bulbs in a sample of 4 bulbs chosen at random.

Formula used :

The probability distribution table is given by , Where P(x) = nCx Here p is the probability of getting a defective bulb.

q = 1 – p

Let the total number of bulbs produced by a machine be x

20% of the bulbs produced by a machine are defective.

Number of defective bulbs produced by a machine = = X denotes the number of defective bulbs in a sample of 4 bulbs chosen at random.

Let p be the probability of getting a defective bulb,

p = = p = q = 1 – p = 1 - = q = since 4 bulbs are chosen at random, n = 4

X can take the values of 0,1,2,3,4

P(x) = nCx P(0) = 4C0 = P(1) = 4C1 = P(2) = 4C2 = P(3) = 4C3 = P(4) = 4C4 = The probability distribution table is as follows, Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

An urn contains 3Mathematics - Board Papers

Two cards are draMathematics - Board Papers

There are three cMathematics - Board Papers

Three numbers areMathematics - Board Papers

Let <span lang="EMathematics - Board Papers

Which of the follRD Sharma - Volume 2

Which of the follRD Sharma - Volume 2

A random variableRD Sharma - Volume 2