Q. 28 C4.8( 4 Votes )

Differentiate eac

Let, y = (3 sec x – 4 cosec x)( – 2 sin x + 5 cos x)

y = – 6 sec x sin x + 15 sec x cos x + 8 sin x cosec x – 20cosec x cos x

y = – 6tan x + 15 + 8 – 20 cot x { tan x cos x = sin x}

y = – 6 tan x – 20 cot x + 23

Differentiating y w.r.t x – Using algebra of derivatives, we have – Use formula of derivative of above function to get the result.  …equation 1

Derivative using product rule –

We have to find dy/dx

As we can observe that y is a product of two functions say u and v where,

u = (3 sec x – 4 cosec x) and v = ( – 2 sin x + 5 cos x)

y = uv

As we know that to find the derivative of product of two function we apply product rule of differentiation.

By product rule, we have – …equation 2

As, u = (3 sec x – 4 cosec x) Use the formula: &   …..equation 3

As, v = – 2 sin x + 5 cos x   …equation 4 { }

from equation 2, we can find dy/dx using equation 3 & 4, we get – sin x = tan x cos x , so we get –   = 20(1 + cot2 x) – 6(1 + tan2 x) [ 1 + tan2 x = sec2 x & 1 + cot2 x = cosec2 x ] Hence, ….equation 5

Clearly from equation 1 and 5 we observed that both equations gave identical results.

Hence, Results are verified

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