Q. 3 J5.0( 1 Vote )

# Differentiate the following from first principles We need to find derivative of f(x) = e√(ax + b)

Derivative of a function f(x) is given by –

f’(x) = {where h is a very small positive number}

derivative of f(x) = e√(ax + b) is given as –

f’(x) = f’(x) = f’(x) = Taking common, we have –

f’(x) = Using algebra of limits –

f’(x) = f’(x) = As one of the limits can’t be evaluated by directly putting the value of h as it will take 0/0 form.

So we need to take steps to find its value.

As h 0 so, ( ) 0

multiplying numerator and denominator by in order to apply the formula – f’(x) = Again using algebra of limits, we have –

f’(x) = Use the formula: f’(x) = Again we get an indeterminate form, so multiplying and dividing √(ax + ah + b) + √(ax + b) to get rid of indeterminate form.

f’(x) = Using a2 – b2 = (a + b)(a – b), we have –

f’(x) = Using algebra of limits we have –

f’(x) = f’(x) = f’(x) = f’(x) = Hence,

Derivative of f(x) = e√(ax + b) = Rate this question :

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