Let X = {<span la

Given, X = {–1, 0, 2, 5}

f : X R Z: f(x) = x3 + 1

Finding f(x) for each value of x,

(1) f(-1) = (-1)3 + 1 = -1 + 1 = 0

(2) f(0) = (0)3 + 1 = 0 + 1 = 1

(3) f(2) = (2)3 + 1 = 8 + 1 = 9

(4) f(5) = (5)3 + 1 = 125 + 1 = 126

f in ordered pair is represented as

f = {(-1,0),(0,1),(2,9),(5,126)}

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