# Find k for which the system 2x + 3y – 5 = 0, 4x + ky – 10 = 0 has a infinite number of solution.

The given two equations are:

2x + 3y – 5 = 0 …(i)

4x + ky – 10 = 0 …(ii)

Here, we have:

a1 = 2, b1 = 3 and c1 = – 5

a2 = 4, b2 = k and c2 = – 10

We know that, for the system having a infinite number of solutions we must have

k = 6

Hence, the value of k is 6

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