Q. 183.8( 4 Votes )

Find k for which the system 2x + 3y – 5 = 0, 4x + ky – 10 = 0 has a infinite number of solution.

Answer :

The given two equations are:

2x + 3y – 5 = 0 …(i)


4x + ky – 10 = 0 …(ii)


Here, we have:


a1 = 2, b1 = 3 and c1 = – 5


a2 = 4, b2 = k and c2 = – 10


We know that, for the system having a infinite number of solutions we must have





k = 6


Hence, the value of k is 6


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