Q. 52

# In a ΔABC, <span

Answer :

In a ∆ ABC,

A + B + C = 180°

[ In any ∆ABC, the sum of all the angles is 180°]

x° + (3x - 2)° + y° = 180°

4x° + y° = 182°.....(1)

and,

C - B = 9° (Given)

- 3x° + y° = 7°.....(2)

Subtracting equation (2) from equation (1), we get -

7x° = 175°

x° = 25°

Substituting the value of x° in equation (2), we get -

y° = 82°

Thus, A = 25°, B = 73° , C = 82°

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