Q. 55.0( 1 Vote )

# . Let f:(2,

Given:

f(x)= : x > 2 and g(x)= :x > 2

(i) To find: (f + g) (x)

Domain(f) = (2, ∞)

Range(f) = (0, ∞)

Domain(g) = (2, ∞)

Range(g) = (2, ∞)

(f + g) (x) = f(x) + g(x)

= Therefore,

(f + g) (x) = (ii) To find:(f - g)(x)

Range(g) Domain(f)

Therefore,

(f - g)(x) exists.

(f - g)(x) = f(x) – g(x)

= Therefore,

(f - g) (x) = (iii) To find:(fg)(x)

(fg)(x) = f(x).g(x)

= = = = Therefore,

(fg)(x) = Rate this question :

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